Passing by reference vs Passing by address

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Something I realised the other day and forget to write down until now:

void swap_ref(int *a, int *b)

{

       int temp = *a;

       *a = *b;

       *b = temp;

}

void swap_add(int &a, int &b)

{

       int temp = a;

       a = b;

       b = temp;

}

These two function do exactly the same thing - swap the values of a and b. The int &a, was created by C++ to stop the unsightly pointers being used. Just keeps code cleaner.

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